3m^2-104=11m

Solution for 3m^2-104=11m equation:

3m^2-104=11m

We move all terms to the left:

3m^2-104-(11m)=0

a = 3; b = -11; c = -104;
Δ = b2-4ac
Δ = -112-4·3·(-104)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-37}{2*3}=\frac{-26}{6}
=-4+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+37}{2*3}=\frac{48}{6}
=8
$